Luas permukaan bangun ruang gabungan di atas adalah
Bangun Ruang
Dik:
Balok 1:
p = 22 cm
l = 8 cm
t = 13 cm
Balok2:
p = 16 cm
l = 8 cm
t = 10 cm
Dit:
Luas Permukaan?
Jawab:
L.p = Balok1 + Balok2
= pl - pl
= 22 × 8 - 16 × 8
= 6 × 8
= (pl + pl) + 2 × (pt + lt) + pl + 2 × (pl + lt)
= 6 × 8 + 22 × 8 + 2 × 22 × 13 + 8 × 13 + 16 × 8 + 2 × 16 × 10 + 8 × 10
= 48 + 176 + 2 × (286 + 104) + 128 + 2 × (160 + 80)
= 224 + 780 + 128 + 480
= 1.612 cm²
[answer.2.content]
